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EE 3230 VLSI Design HW #1 solved

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1. Use a combination of 2-input CMOS logic gates (in gate-level symbols) to generate the
schematics for the following functions from inputs of A, B, and C.
Then complete the stick diagrams for each of the following functions according to the
schematics you draw.
(a) Y=A’+B’(15%)
(b) Y=A’B’C’(15%)
(c) Y=AC+BC+B’ (15%)
2. Draw the fabrication steps of an inverter (cross section).
Explain the “self-aligned poly-silicon gate” as well as “lightly-doped drain (LDD)”. (35%)
3. Please simulate and analyze a CMOS inverter according to the following conditions
using the model provided by TA (CIC018.l).
* Set the supply voltage to 1.8 V.
* Set the output load of this inverter to 0.15 pF.
* Use the minimum channel length for both NMOS and PMOS.
* Use the minimum channel width for NMOS.
3a) Find and report the optimal width for PMOS for a balanced trigger point of inverter
at TT corner and 25°C. The meaning of a balanced trigger point is as the following.
Vin = Vout = 0.5×VDD (That is to say, Vout equals to Vin when Vin is set to half of VDD.)
3b) Perform DC sweep and plot Vout vs. Vin as Vin sweeps from 0 V to VDD with the
step of 0.05 V in five different process/temperature corners.
3c) Repeat 3b) with the NMOS width set to 5X of minimum channel width. Then
complete the following table. (Report Vout value when Vin is set to half of VDD.)
Process Temperature
NMOS width 1X NMOS width 5X
Vout
at Vin=0.5×VDD
Vout
at Vin=0.5×VDD
TT 25°C
FF –40°C
SS 125°C
SF 25°C
FS 25°C
4. Follow the previous question, run transient simulations for all 10 conditions and
measure the input to output delay of the inverter. Set the rise and fall time of the input
waveforms to 1 ns.
Attach the simulated waveforms for TT 25°C (with rise and fall time labeled clearly) for
both 1X NMOS and 5X NMOS.
Process Temperature
NMOS width 1X NMOS width 5X
Fall Delay Rise Delay Fall Delay Rise Delay
TT 25°C
FF –40°C
SS 125°C
SF 25°C
FS 25°C