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COMP 322 Assignment 3: Object Oriented Design solved

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Part One [70 points]
In this assignment we will tackle the implementation of a very simplified version of
the famous BlackJack card game. We will drop all the complicated rules and we will
consider that the game is played by one player against the computer.
The simplified rules are like this:
● Each card has a numerical value.
○ Numbered cards are counted at their face value (two counts as 2
points, three, 3 points, and so on)
○ An Ace count as either 1 point or 11 points (whichever suits the player
best)
○ Jack, queen and king count 10 points each
● The player will compete against the computer which represents the casino.
● The goal of the player is to try to reach a total point sum of 21 without
exceeding it. Whoever exceeds 21 first loses (technically known as busting).
● At the beginning of each round, the player is dealt two open cards and the
computer is dealt one open card. The cards are open, meaning that the
values are known for both the player and the computer (no hidden cards).
● The player will see the sum of the points from his 2 open cards and decide
whether or not to draw an additional card.
● The player may draw one additional card at a time for as long as he likes or
until he busts (sum of drawn cards exceeds 21). If he busts, he loses the
round.
● When the player decides that he won’t draw anymore and he is happy with
whatever total amount he got, the computer will draw and open an
additional card.
● The computer will keep on drawing additional cards, one at a time as long as
the sum of its cards is less or equal 16.
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● If the computer busts, the player wins.
● If the computer doesn’t bust (total sum is less or equal 21), then the total
values are compared between the computer and the player. Whomever has a
higher value wins the round.
● If the two totals are the same, no one wins the round (technically called a
push).
We will add a twist to the rules to give the casino a higher probability of
winning. To do so, we need to keep track of the history of all the rounds to
know how many rounds the player has won VS the casino. When we find that
the casino is losing more rounds than the player (casino is winning less than
55% of the time), we need to trick the randomness of the cards in order to
give the casino a tiny push and maintain a percentage of winning around 55%
for the casino.
Here is a list of all the needed classes to code the game:
● Card: represents a card. Each card has a rank and a type which can be easily
represented via enums.
○ Rank is one of the following {ACE = 1, TWO, THREE, FOUR, FIVE, SIX, SEVEN,
EIGHT, NINE, TEN, JACK, QUEEN, KING}
○ Type is one of the following {CLUBS, DIAMONDS, HEARTS, SPADES}
○ Card class must have the following methods:
■ getValue that would return the numerical value of a card
■ displayCard that would print to the screen the card information. For
example 1H means ace of hearts, 2D means two of diamonds, QS
means queen of spades and so on.
● Hand: represents the set of cards that the player or the computer holds. This class
should contain a list of cards that can be implemented as an array or a vector or any
data structure that you prefer. It should also have the following methods:
○ add that would add a card to the hand
○ clear that would clear all the cards from a hand (removing them)
○ getTotal that would get the total sum of the cards numerical values
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● Deck: represents the deck of cards and the actions that can be performed on the
cards like shuffling and dealing. This class may inherit from the Hand class for
convenience but I keep it up to you to decide whether you would inherit or not.
Deck should implement the following methods:
○ Populate will create a standard deck of 52 cards
○ shuffle will shuffle the cards
○ deal will deal one card to a hand
● AbstractPlayer: represents a generic abstract player that can be a human or the
computer. This is an abstract class meaning that it has a pure virtual method. The
methods that this class have are:
○ virtual bool isDrawing() const = 0; which is a pure virtual method that
indicates whether a player wants to draw another card.
○ isBusted that returns true if a player has busted (sum of cards exceeds 21).
Note that AbstractPlayer may inherit from Hand for convenience but this is
left totally to you to decide.
● HumanPlayer: represents the human player. This class inherits AbstractPlayer and
should have the following methods:
○ isDrawing implements the inherited method that indicates whether a player
wants to draw another card
○ announce a method that prints information about whether the player wins,
loses or has a push situation.
● ComputerPlayer: represents the computer (the casino). This class inherits
AbstractPlayer and should have the following method:
○ isDrawing implements the inherited method that indicates whether the
computer should be drawing another card. Remember that the rules for the
computer are different. The computer should keep on drawing an
additional card as long as the sum of its cards is less or equal 16. This
method should take the percentage of winning into consideration. If
the percentage is less than 55%, then you need to implement some
logic to make sure that the casino gets better chances of winning.
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● BlackJackGame: a class representing the overall game. This class must have the
following data members:
○ A Deck data member m_deck
○ A ComputerPlayer member m_casino
It should also implement the following method:
○ play that plays the game of blackjack
Use the following main function to run the game:
int main()
{
cout << “\tWelcome to the Comp322 Blackjack game!” << endl << endl;
BlackJackGame game;
// The main loop of the game
bool playAgain = true;
char answer = ‘y’;
while (playAgain)
{
game.play();
// Check whether the player would like to play another round
cout << “Would you like another round? (y/n): “; cin >> answer;
cout << endl << endl;
playAgain = (answer == ‘y’ ? true : false);
}
cout <<“Gave over!”;
return 0;
}
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The output while playing the game should be something similar to this:
Welcome to the Comp322 Blackjack table!
Casino: 8S [8]
Player: 4C 9D [13]
Do you want to draw? (y/n):y
Player: 4C 9D 7C [20]
Do you want to draw? (y/n):n
Casino: 8S 2H [10]
Casino: 8S 2H 9S [19]
Player wins.
Would you like another round? (y/n):y
Casino: 1S [11]
Player: 1C 2H [13]
Do you want to draw? (y/n):y
Player: 1C 2H 10D [13]
Do you want to draw? (y/n):y
Player: 1C 2H 10D KH [23]
Player busts.
Casino wins.
Would you like another round? (y/n):y
Casino: QS [10]
Player: 4C 4H [8]
Do you want to draw? (y/n):y
Player: 4C 4H 3S [11]
Do you want to draw? (y/n):y
Player: 4C 4H 3S JC [21]
Casino: QS 1C [21]
Push: No one wins.
Would you like another round? (y/n):n
Gave over!
Grading scheme:
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● Proper calculation of the Ace value (1 vs 11) as per the instructions: 3 points
● Rank and type implemented properly as enum: 2 points
● Card::getValue() and Card::displayCard(): 10 points (5 each)
● Hand:: add, clear, getTotal: 12 points (4 each)
● Deck:: populate, shuffle, deal: 12 points (4 each)
● AbstractPlayer::isBusted: 4 points
● AbstractPlayer::isDrawing pure virtual and const: 4 points
● HumanPlayer::isDrawing , annouce : 8 points (4 each)
● ComputerPlayer::isDrawing: 5 points
● BlakJackGame::play(): 6 points
● Keeping track of winning history and maintaining a 55% chance of winning to the
casino: 4 points
Part Two [30 points]
Modify your implementation to accommodate for a multi-hand game. This means that the
same player can have 1, 2 or 3 hands at the same table. The maximum number of hands
that a player can have at the same time is 3.
If the player chooses to have 3 hands, this means that the player will act as if he (or she)
were 3 different players. The player can win some hands and lose some others. The player
will be drawing for the 3 different hands one after the other.
Clone your code from part 1 and modify it to accommodate the new requirements. Please
make sure to submit the versions separately.
Same rules apply as before. Modify the output to reflect the new reality.
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